140k^2-76k-96=0

Solution for 140k^2-76k-96=0 equation:

140k^2-76k-96=0

a = 140; b = -76; c = -96;
Δ = b2-4ac
Δ = -762-4·140·(-96)
Δ = 59536
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{59536}=244$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-76)-244}{2*140}=\frac{-168}{280}
=-3/5
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-76)+244}{2*140}=\frac{320}{280}
=1+1/7
$